48a=20a^2=0

Solution for 48a=20a^2=0 equation:

48a=20a^2=0

We move all terms to the left:

48a-(20a^2)=0

determiningTheFunctionDomain
-20a^2+48a=0

a = -20; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-20)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-20}=\frac{-96}{-40}
=2+2/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-20}=\frac{0}{-40}
=0
$